01BMHM05数学Ⅱ-06-微分法と積分法
IIB 数学演習問題
1
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New 2 ͭͷ์ઢ C1 : y = x² C2 : y = x² − 6x + 15 ͷڞ௨ઢͷํఔࣜΛٻΊΑɻ
- Ԡ New f(x) = ax² + bx + c g(x) = x³ + dx ͱ͢Δɻ ࣍ͷ 2 ͭͷ݅ (a)ɼ(b) Λͱʹຬͨ͢Α͏ʹఆ a, b, c, d ͷΛఆΊΑɻ (a) ۂઢ y = f(x) (1, −3) Λ௨Δɻ (b) ۂઢ y = f(x) ͱۂઢ y = g(x) (2, 6) ʹ͓͍ͯڞ௨ͷઢΛͭɻ
ʲղʳ
- y = 2x − 1
- (a, b, c, d) = (2, 3, −8, −1)
2
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- New ؔ f(x) = x³ + ax² + 3x + 4 ͕ۃΛͭΑ͏ʹɼఆ a ͷͷൣғΛఆΊΑɻ
- New ؔ y = x³ − 3ax² + 3x + 1 ͕୯ௐʹ૿Ճ͢ΔΑ͏ʹɼఆ a ͷͷൣғΛٻΊΑɻ
- Ԡ New ؔ f(x)=2x³ − 3(a + 2)x² + 12ax ͕͋Δɻ (1) f(x) ͕ۃΛͨͳ͍Α͏ʹɼఆ a ͷͷൣғΛఆΊΑɻ (2) f(x) ͕ۃΛͭͱ͖ɼۃେΛ a Ͱදͤɻ
ʲղʳ
- a < −3 , 3 < a
- −1 ≤ a ≤ 1
- (1) a = 2 (2) a < 2 ͷͱ͖ −a³ + 6a² 2 < a ͷͱ͖ 12a − 8
3
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- New ࣍ͷؔͷάϥϑΛ͔͚ɻ (1) y = x⁴ − 2x² (2) y = x⁴ − 6x² − 8x
- New ؔ y = −½ x⁴ − 2x + 3 ͷ −2 ≤ x ≤ 3 ʹ͓͚Δ࠷େͱ࠷খΛٻΊΑɻ
ʲղʳ
- چ BW ɹؔͷͷมԽʢ̎ʣ࿅श (1)(2) ͷղΛૠೖ͍ͯͩ͘͠͞ɻ 9 େ࠷ 2
- (x = −1) ɹ࠷খ − 87 2 (x = 3)
4
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New ࣮ x, y ͕ x² + y² = 4 Λຬͨ͢ͱ͖ɼxy² − 2x² ͷ࠷େͱ࠷খΛߟ͑Δɻ (1) x ͷऔΓ͏ΔͷൣғΛٻΊΑɻ (2) xy² − 2x² ͷ࠷େͱ࠷খΛٻΊΑɻ
- Ԡ New 0 ≤ x ≤ π ͷͱ͖ɼؔ y = 4 sin³θ + cos²θ − 2 sinθ + 1 ͷ࠷େͱ࠷খΛٻΊΑɻ
ʲղʳ
- (1) −2 ≤ x ≤ 2 (2) ࠷େ 40/27 ɼ࠷খ −8
- ࠷େ 3ɼ࠷খ 5/4
5
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New a > 0 ͱ͢Δɻؔ f(x) = x³ − 3x + 1 (0 ≤ x ≤ a) ʹ͍ͭͯɼ࣍ͷ͍ʹ͑Αɻ (1) ࠷খΛٻΊΑɻ (2) ࠷େΛٻΊΑɻ
- Ԡ New a > 0 ͱ͢Δɻؔ f(x) = x³ − 3a²x (0 ≤ x ≤ 1) ʹ͍ͭͯɼ࣍ͷ͍ʹ͑Αɻ (1) ࠷খΛٻΊΑɻ (2) ࠷େΛٻΊΑɻ
ʲղʳ
- (1) 0 < a < 1 ͷͱ͖ a³ − 3a + 1ɼ1 ≤ a ͷͱ͖ −1 (2) 0 < a < 3 ͷͱ͖ 1ɼ3 ≤ a ͷͱ͖ a³ − 3a + 1
- (1) 0 < a < 1 ͷͱ͖ −2a³ɼ1 ≤ a ͷͱ͖ 1 − 3a² (2) 0 < a < 1/√3 ͷͱ͖ 1 − 3a²ɼ 1/√3 ≤ a ͷͱ͖ 0
6
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New ۂઢ y = x³ + 3x² ʹ͍ͭͯɼۂઢʹ (1, p) ͔ΒҟͳΔ 3 ຊͷઢ͕Ҿ͚ΔΑ͏ͳఆ p ͷͷൣғΛٻΊΑɻ
- Ԡ New 3 ࣍ํఔࣜ x³ − 3a²x + 4a = 0 ʹ͍ͭͯɼҟͳΔ 3 ݸͷ࣮ղΛͭ a ͷͷൣғΛٻΊΑɻ
ʲղʳ
- −4 < p < 4
- a < −√2 , √2 < a
7
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- New x ≥ 0 ͷͯ͢ͷ x ʹରͯ͠ɼෆࣜ 2x³ − 12x² + 18x + k ≥ 0 ͕ΓཱͭΑ͏ͳఆ k ͷͷൣғΛٻΊΑɻ
- Ԡ New x ≥ 0 ͷͱ͖ɼෆࣜ x³ + 32 − px² ͕ΓཱͭΑ͏ͳఆ p ͷͷൣғΛٻΊΑɻ
ʲղʳ
- k ≥ 0
- p ≥ 6
8
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New ࣜ f(x) = x + 3 + ∫₋₁ˣ (x − t)f(t) dt Λຬͨؔ͢ f(x) ΛٻΊΑɻ
- x ∈ [1, 2] ∫₁ˣ f(t) dt = x² − kx + 9 Λຬͨؔ͢ f(x) ͱఆ k ͷΛٻΊΑɻ
- New ࣍ͷ݅Λຬͨ͢ 2 ࣍ؔ f(x) ΛٻΊΑɻ f(1) = 1 , f(−1) = −1 , ∫₋₁¹ f(t) dt = 4
ʲղʳ
- f(x) = 3x + 1
- f(x) = x² − 10x + 9 , k = 10
- f(x) = −3x² + x + 3
9
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New ۂઢ y = −x² + 2x ͱ x ࣠Ͱғ·Εͨ෦ͷ໘ੵΛɼઢ y = (−a + 2)x ͕ 2 ͢ΔΑ͏ʹɼఆ a ͷΛఆΊΑɻ
- Ԡ New (−1, 2) Λ௨Δ͖ m ͷઢͱɼ์ઢ y = x² Ͱғ·Εͨਤܗͷ໘ੵΛ S ͱ͢Δɻ m ͕ͯ͢ͷ࣮ΛͱͬͯมԽ͢Δͱ͖ɼS ͷ࠷খͱͦͷͱ͖ͷ m ͷΛٻΊΑɻ
ʲղʳ
- a = √3/4 4 খ࠷ 2
- (m = −2)
10
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- ์ઢ C : y = x² − 5x + 8 ʹ (3, 1) ͔Β 2 ຊͷઢΛҾ͘ͱ͖ (1) ͜ͷ 2 ຊͷઢͷํఔࣜΛٻΊΑɻ (2) ์ઢͱ 2 ຊͷઢͰғ·Εͨ໘ੵΛٻΊΑɻ
- Ԡ New 2 ͭͷ์ઢ C1 : y = x² − 5x + 7 , C2 : y = x² + 3x − 1 ͷ྆ํʹ͢ΔઢΛ ͱ͢Δɻ (1) ઢ ͷํఔࣜΛٻΊΑɻ (2) C1.C2, Ͱғ·Εͨਤܗͷ໘ੵΛٻΊΑɻ
ʲղʳ
- (1) y = −x + 4 , y = 3x − 8 (2) 2/3
- (1) y = x − 2 (2) 16/3
11
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- New ࣍ͷۂઢͱઢͰғ·Εͨ໘ੵΛٻΊΑɻ (1) y = x²(x − 2) ͱ x ࣠ (2) y = x(x − 1)(x − 2) ͱ x ࣠
- Ԡ New ۂઢ C : y = x³ − x + 1 ʹ͍ͭͯɼ࣍ͷ͍ʹ͑Αɻ (1) (0, −1) Λ௨Δઢ ͷํఔࣜΛٻΊΑɻ (2) ۂઢ C ͱઢ Ͱғ·Εͨਤܗͷ໘ੵΛٻΊΑɻ
ʲղʳ
- (1) 4/3 (2) 1/2
- (1) y = 2x − 1 (2) 27/4
12
New ͕͍͍ͯΔɼ͜ͷतۀͰ৽ग़ͷࣄ߲Ͱ͢ɻ෮शͷࡍॏʹࢹ͍ͯͩ͘͠͞ɻ
- Ԡ New ۂઢ C : y = |x² − 2x| ͱઢ : y = x Ͱғ·Εͨ 2 ͭͷ෦ͷ໘ੵͷΛٻΊΑɻ
- ൃల New ؔ f(t) Λ f(t) = ∫₋₁¹ |x² − t²| dx (t ≥ 0) Ͱఆٛ͢Δɻ (1) f(t) ΛٻΊΑɻ (2) t ≥ 0 ʹ͓͚Δ f(t) ͷ࠷খΛٻΊΑɻ
ʲղʳ
- 13/6
- (1) 0 ≤ t ≤ 1 ͷͱ͖ f(t) = 8/3 t³ − 2t² + 2/3 ɼ1 < t ͷͱ͖ f(t)=2t² − 2/3 (2) 1/2
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